There is a theorem of complex analysis, which is in a common use and almost nobody knows its origin. Literka
analyzed all threads and realized that it was proved by Professor Walter Rudin. Since nobody indicates the
origin of this theorem, Literka decided to write a page about it.
Theorem uses only basic definitions, but for completeness let us remind that:
Two functions f and g with values in a complex plane are called equidistributed,
if for any measurable set A of this plane
the sets
have the same measures.
Let
be a unit disk of a complex plane and T be a unit circle of U (set of all z with the absolute
value 1).
We do not want to introduce whole theory - let us mention only that interesting us analytic functions
defined on U have boundary values on T and these functions are determined by the boundary values on T.
Analytic function f defined on U, with absolute values
bounded by 1 on U, is called inner if almost all boundary values of f (hence we regard f as function on T)
have absolute values 1 (hence belong to T). That is why we can say that an inner function is a function
defined on T with the range in T.
On T there is defined "normalized length" measure
in the ordinary way, assuming measure of T is equal 1.
The simplest inner function is the identity function f(z)=z or any power of it.
Theorem (Rudin). All inner functions
such that f(0)=0 are equidistributed on T, with respect to the measure
.
Before we prove this theorem let us write few comments.
Of course, from this theorem it follows that all such inner functions must be equidistributed with the
function I(z)=z. Since I is a measure-preserving function, all inner funtions f with f(0)=0
must be measure-preserving.
Some time ago, when Literka did not know Rudin's theorem, Literka took a part in a private conversation, when
somebody asked about possible values of the expression
where B(z) is a Blaschke product and we integrate with respect to the "normalized length" measure on T
(Blaschke products are special cases of inner functions).
After some computations they reached a proper answer. Literka writes about it because
Rudin's theorem gives an immediate answer that
there is only one value equal to (we replace z instead of z*B(z))
The real advantage of this theorem is that it has a nice and straightforward proof:
Proof of Rudin's theorem.
Let f be an inner function satisfying the assumptions of the Theorem and let A be a subset of T. We'll prove
that f is a measure-preserving function. We'll denote
to be a characteristic function of a set A. We have
Hence it is enough to prove that if h is a characteristic function of any set, then
We'll prove more: that it is true for any measurable function h. Since countinuous functions are dense in
the space of all measurable functions, it is enough to prove it for the case h is a continuous function.
The above equality is true for the functions
Assume first that n is positive. Then
For n=0 we have
Let us notice that
for z belonging to T.
Finally for negative n we have
Finally let us make a remark that if the equality holds for these functions, it must hold for linear
combinations of these functions. But linear combinations of these functions are dense in the space of
continuous functions (Weierstrass theorem), which proves our statement.
Notice: Andreas Sauer wrote Literka that the above proof is in the book of Professor Walter Rudin
"New constructions of functions holomorphic in the unit ball of C^n", AMS, 1986,
(Theorem 1.3)